"Proof: x=0x)
."
"Hence 1.14(b) implies that 
."
As shown above, 
.
"Then (a) gives (\frac{1}{x})xy=(\frac{1}{y})(\frac{1}{x})%20\cdot%200=0)
."
"The first equality in (c) comes from y+xy=(-x+x)y=0y=0)
, combined with 1.14(c)."
Then y+xy=0)
, and by 1.14(c), y=-(xy))
.
"The other half of (c) is proved in the same way."
Then +xy=0)
, and by 1.14(c), =-(xy))
.
"Finally, (-y)=-(x(-y))=-(-(xy))=xy)
by (c) and 1.14(d)."
No comments:
Post a Comment